help me
The length of the shadow of a building is 90 meters, as shown below: What is the height of the building? 180 m 51.96 m 155.88 m 60 m i know i have to find the adjacent i believe but i just need someone to guide me
@jim_thompson5910
\[\Huge \tan \theta = \frac{perpendicular}{base}\]
|dw:1404247333746:dw|
and all you need to know is that \[\Huge \tan 30 = \frac{1}{\sqrt 3}\]
i did something similar with someone earlier so i think it should be easy for me to understand
okay let me solve it
\[\Huge \frac{1}{\sqrt 3 } = \frac{H}{90}\] Solve for H.
cross multiply?
yep then divide both sides by root 3
52?
what did you do? H should be \[\Huge H=\frac{90}{ \sqrt 3}\]
to change the form, \[\LARGE H = \frac{90}{\sqrt 3} \times \frac{\sqrt 3}{\sqrt 3} = 30 \sqrt 3\]
i know then i get 52?
i got 51.96 and i rounded
oh..u wrote an exact answer so I thought u did smt wrong XD its okay
i submitted it and got 100% thanks for all the help
uw
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