Question

Please help me check if I am going the the right direction..solve squire-root of 2x+15=x+2

Answer 1

no you should make the equation equals zero
its more easier for you

Answer 2

\[\sqrt{2x+15} = x+2\]

Answer 3

okay check what i did

Answer 4

try make it like this
\[\sqrt{x + 13}\]

Answer 5

=0

Answer 6

\[\sqrt{2x+15}= x+2 =(\sqrt{2x+15)^{2}}\]

Answer 7

what is that ?

Answer 8

\[\sqrt{2x+15}=x+2 =2x+15=(x+2)^2, =2x+15=x^2+4x+4\]

Answer 9

now i solve for x\[x^2+4x+4=2x+15=x^2+4x+4-2x-15=0\]

Answer 10

=x^2+2x-11=0

Answer 11

so the first WAS a root !!

Answer 12

yes

Answer 13

that is another thing then
but you wrote them both with no roots

Answer 14

the question is\[\sqrt{2x+15}=x+2\]

Answer 15

then square them to find x

Answer 16

it`ll be x = {\[\frac{ -2+\sqrt{48} }{ 2 } , \frac{ -2-\sqrt{48} }{ 2 }\]}

Answer 17

where did you get 48

Answer 18

Actually, simplifying that you get \[-1\pm2\sqrt{3}\]