I want a elegant method to solve this question i have already solved it though.
The sum of three numbers in an G.P is 70 , the two extremes be multiplied each by 4 and the mean by 5, the products are in A.P . Find the numbers
I am getting two values of "r" the common differnce
I need to see the original wording
wording? that is the exact question as from the textbook
the question is not clearly stated
let the final numbers in AP be a-d,a,a+d then (a-d)/4 ,a/5 ,(a+d)/4 add upto 70
and these are in GP too
Well i considered a/r , a , ar
so a/2 +a/5 =70 so a= 100
but the mean of the GP is 20
a +ar + ar^2 =70r a(1+r+r^2) =70r From the second piece of information I got 4r^2 -10r +4 =0 and thus r = 1/2 and 2
I don't actually need extra large explanation and information , i will understand and percieve no problem
|dw:1404279060854:dw| |dw:1404279234414:dw| 10, 20 and 40
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