WILL GIVE MEDAL The area of a rectangle is given by the expression x^3 + x^2 – 11x – 30. If the length of the rectangle is given by the expression x^2 – x – 6, find the expression that represents the width.
@Miracrown
well if you factorize the area you will get two factors one is the length and the other is the width and since you have the equation of the length you will easily find the width
or you can simply just divide the area over the length
I come up with B? A. x – 5 B. x + 5 C. x^2 – 5 D. x^2 + 5
is the equations in the questions are copied correctly ?
The area of a rectangle is given by the expression x^3 +4 x^2 – 11x – 30. If the length of the rectangle is given by the expression x^2 – x – 6, find the expression that represents the width.
see !! there is no (4x^2) in the question
so yes its B
haha sorry! Thank you!!
yw
You can do this two ways: You can use long division and divide \(x^3 +4 x^2 – 11x – 30\) by \(x^2 – x – 6\). Since you are given choices, you can also look at it this way. \(\color{red}{x^3} + 4x^2 - 11x \color{blue}{-30} = (\color{red}{x^2} - x \color{blue}{- 6})(\color{red}{A} + \color{blue}{B})\) \(x^2 \times A = x^3\). That means \(A = x\) \(-6 \times B = -30\). That means \(B = 5\). That means the answer must be \(x + 5\).
makes much more sense! Thank you everyone!
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