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Mathematics 7 Online
OpenStudy (anonymous):

Sum of n terms in a harmonic progression

OpenStudy (anonymous):

I am asking

OpenStudy (ikram002p):

do you have a harmonic progression ?

OpenStudy (anonymous):

no in general

OpenStudy (ikram002p):

but he ask about Sum of n terms , so integrate might work :D

OpenStudy (ikram002p):

or that would be approximation ?

ganeshie8 (ganeshie8):

how does one integrate a floor function \[\large \int \limits_1^{\infty}\dfrac{1}{[x] } - \dfrac{1}{x} dx\]

ganeshie8 (ganeshie8):

*\[\large \int \limits_1^{\infty}\dfrac{1}{\lfloor x \rfloor } - \dfrac{1}{x} dx\]

OpenStudy (ikram002p):

by common sense mmm its descrete so try to make conjecture

OpenStudy (ikram002p):

but i think we dnt need floor function mmm 1/x it self should be fine approximation

ganeshie8 (ganeshie8):

\[\int \limits_1^n \lfloor x\rfloor = 1 + 2 + 3 + \cdots (n-1)\] ?

ganeshie8 (ganeshie8):

\[\int \limits_1^{n} \dfrac{1}{\lfloor x\rfloor} dx = \dfrac{1}{1} + \dfrac{1}{2} + \dfrac{1}{3} + \cdots + \dfrac{1}{n-1}\]

ganeshie8 (ganeshie8):

hmm

ganeshie8 (ganeshie8):

\[\ln n \ne \int \limits_1^{n} \dfrac{1}{\lfloor x\rfloor} dx = \dfrac{1}{1} + \dfrac{1}{2} + \dfrac{1}{3} + \cdots + \dfrac{1}{n-1} \]

OpenStudy (ikram002p):

lets refare to integration definition

OpenStudy (ikram002p):

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