Sum of n terms in a harmonic progression
I am asking
do you have a harmonic progression ?
no in general
but he ask about Sum of n terms , so integrate might work :D
or that would be approximation ?
how does one integrate a floor function \[\large \int \limits_1^{\infty}\dfrac{1}{[x] } - \dfrac{1}{x} dx\]
*\[\large \int \limits_1^{\infty}\dfrac{1}{\lfloor x \rfloor } - \dfrac{1}{x} dx\]
by common sense mmm its descrete so try to make conjecture
but i think we dnt need floor function mmm 1/x it self should be fine approximation
\[\int \limits_1^n \lfloor x\rfloor = 1 + 2 + 3 + \cdots (n-1)\] ?
\[\int \limits_1^{n} \dfrac{1}{\lfloor x\rfloor} dx = \dfrac{1}{1} + \dfrac{1}{2} + \dfrac{1}{3} + \cdots + \dfrac{1}{n-1}\]
hmm
\[\ln n \ne \int \limits_1^{n} \dfrac{1}{\lfloor x\rfloor} dx = \dfrac{1}{1} + \dfrac{1}{2} + \dfrac{1}{3} + \cdots + \dfrac{1}{n-1} \]
lets refare to integration definition
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