Question

write the function f(x)= 2x^2+8x+7 in the form of f(x)= a(x-h)^2 + k and find the vertex

Answer 1

first complete the square... are u familiar in completing the square..?

Answer 2

no im not

Answer 3

i'm not quite sure how to complete the square

Answer 4

separate 2x^2 + 8x from 7

when u complete the square... u get the half of 8 and square it, then add it to both sides.

\[2x^2+8x+(\frac{ 8 }{ 2 })^2 = -7\]
\[2x^2+8x+(4)^2 = -7+(4)^2\]

Answer 5

whats the answer..?

Answer 6

um.. 2x^2+8x+16=9 ?

Answer 7

its -9..

Answer 8

so now factor that..can u do it ..?

Answer 9

im still confused.

Answer 10

why is it negative 9?

Answer 11

ah sorry... its positive... anyway can u factor it in the form a(x-h)^2 + k..?

Answer 12

and then how do i know what point the vertex would be?

Answer 13

so the form that it should be is f(x)= 2(x+2)^2 -9 ?