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Mathematics 8 Online
OpenStudy (anonymous):

Use the given triangles to evaluate the expression. Rationalize all denominators. cos Pi/6

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

Hang on, what is the expression?

OpenStudy (anonymous):

it is in the very first attchment

OpenStudy (anonymous):

that is all it has

OpenStudy (anonymous):

@johnweldon1993 oh its cos pi/6

OpenStudy (anonymous):

@Garadon_Shagan

OpenStudy (johnweldon1993):

Ah okay lol, yeah I was like...are you sure? regardless...Alright what does \(\Large \frac{\pi}{6}\) equate to in degrees?

OpenStudy (anonymous):

i have no clue lol

OpenStudy (johnweldon1993):

To convert to degrees we multiply by \(\large \frac{180}{\pi}\) so \[\large \frac{\pi}{6} \times \frac{180}{\pi}\] \[\large \frac{180\cancel{\pi}}{6\cancel{\pi}}\] so what is 180/6?

OpenStudy (anonymous):

is it 30?

OpenStudy (johnweldon1993):

Right! That, is what tells us which triangle to use, we use the triangle with 30 degrees in it

OpenStudy (anonymous):

Ok i am following you

OpenStudy (johnweldon1993):

So now We look at that triangle |dw:1404318940521:dw|

OpenStudy (johnweldon1993):

WE need to focus on |dw:1404318986537:dw| the 30 degree mark

OpenStudy (johnweldon1993):

Now, What does \(\large \cos\) equal? (in regards to right triangles)?

OpenStudy (anonymous):

how do i figure that out? im sorry i know i am alot of trouble

OpenStudy (johnweldon1993):

No not at all, but I should assume that you have seen \[\large \cos = \frac{adjacent}{hypotenuse}\] right?

OpenStudy (anonymous):

yes but i dont remember how to figure it out

OpenStudy (johnweldon1993):

Oh, well there isn't exactly a way to figure it out...but there is a good way to remember the 3 basic trig functions SOH-CAH-TOA Think about it like this Some Old Horse: Sin Opposite Hypotenuse Caught Another Horse: Cos Adjacent Hypotenuse Tripping On Acid: Tan Opposite Adjacent Good little memory thing there :)

OpenStudy (anonymous):

i like that ^ lol :)

OpenStudy (johnweldon1993):

Good :) lol Alright so with this We know \[\large \cos = \frac{adjacent}{hypotenuse}\] So from that angle...we need the side adjacent to that...and we need the hypotenuse of the triangle

OpenStudy (johnweldon1993):

|dw:1404319328460:dw| So...since cos = adjacent/hypotenuse... we will have \[\large \cos = \frac{\sqrt{3}}{2}\]

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