Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two over three the distance from point P to point R

Question

anonymous · Answer

4.9

 4.7

 2.5

 2.3

amistre64 · Answer

any point in an interval can be assessed by simply adding some percentage of the difference to the starting value

given an interval from a to b,  then some c in the interval has the value:$$x=a+\kappa(b-a)$$
$$c=a+\kappa b-\kappa a$$
$$c=(1-\kappa)a+\kappa b$$
so in your case, x=(1-2/3)(-2) + (2/3)(1)  is a good assessment to start with

amistre64 · Answer

can you find y in the same manner?

anonymous · Answer

what is the answer please

amistre64 · Answer

we are not a free answering service.  i provided you with a method to approach a soltuon and demonstarted it for you.  you either need to ask what you dont understand about the process, or give it a try.

anonymous · Answer

well i dont understand how to solve

amistre64 · Answer

find the distance between your y parts,  and multiply it by 2/3

then add that to the start of it all

amistre64 · Answer

your y parts start at 7 and end at 0|dw:1404334974386:dw|