Mathematics
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OpenStudy (jenniferjuice):
Calculate the average rate of change for the function f(x) = −x4 + 4x3 − 2x2 + x + 1, from x = 0 to x = 1.
0
1
2
7
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myininaya (myininaya):
to find the average rate use the formula to find the slope of the secant line going though f from x=0 to x=1.
that is \[\frac{f(1)-f(0)}{1-0}\]
OpenStudy (jenniferjuice):
f1/1?
myininaya (myininaya):
f(0)=?
OpenStudy (jenniferjuice):
is my answer 1 ?
myininaya (myininaya):
what is f(1)?
what is f(0)?
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OpenStudy (triciaal):
find f(x) when x = 1
find f(x) when x = 0
OpenStudy (triciaal):
isn't the rate of change the derivative of the function?
myininaya (myininaya):
yep
but it says average rate of change
myininaya (myininaya):
which just calls for the slope formula without all the limit stuff
OpenStudy (jenniferjuice):
so what do i do..?
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myininaya (myininaya):
triciaal said you need to find f(x) when x=1 and also for x=0
myininaya (myininaya):
then plug into the above formula i mentioned
OpenStudy (triciaal):
@myininaya is your answer 7?
myininaya (myininaya):
Let's go in steps @jenniferjuice
Can you find f(1)?
myininaya (myininaya):
you said f(x)=-x^4+4x^3-2x^2+x+1
you should be able to replace all the x's there with 1's to find f(1)
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myininaya (myininaya):
like so f(1)=-1^4+4(1)^3-2(1)^2+1+1
myininaya (myininaya):
now simplify that.
OpenStudy (jenniferjuice):
how?
myininaya (myininaya):
what is 1^4?
myininaya (myininaya):
\[f(1)=-1^4+4(1)^3-2(1)^2+1+1 \\ -1+4(1)^3-2(1)^2+1+1\]
so above i replaced 1^4 with 1
you should know what 1^3 and 1^2 is...
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myininaya (myininaya):
1^4=1*1*1*1=1
1^3=1*1*1=?
1^2=1*1=?
1 to any power equals?
OpenStudy (jenniferjuice):
1
myininaya (myininaya):
right so replace the 1^n 's with 1
OpenStudy (jenniferjuice):
-1+4-2+2
myininaya (myininaya):
\[f(1)=-1^4+4(1)^3-2(1)^2+1+1 \\ -1 +4(1)-2(1)+1+1\]
right -1+4-2+2
this can be simplified more
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OpenStudy (jenniferjuice):
-1+4-2+2
-1+4-4
3-4
-1
myininaya (myininaya):
-2+2 isn't 4 or -4
myininaya (myininaya):
if you a credit of 2 then a debit of 2
then you have?
OpenStudy (jenniferjuice):
0
myininaya (myininaya):
so -2+2 is 0
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myininaya (myininaya):
so -1+4 =?
OpenStudy (jenniferjuice):
3
myininaya (myininaya):
right so f(1) is 3
what is f(0)?
myininaya (myininaya):
f(0) should be the easiest to find
OpenStudy (jenniferjuice):
is it 0
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myininaya (myininaya):
nope
myininaya (myininaya):
remember f(0) tells you to use the machine (function ) that is labeled f
myininaya (myininaya):
f(x)=-x^4+4x^3-2x^2+x+1
myininaya (myininaya):
to find f(0) replace every single x there with 0 then simplify
myininaya (myininaya):
look if you replace all of those x's with 0
won't you just have 0+0-0+0+1?
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OpenStudy (jenniferjuice):
yes so 1
OpenStudy (jenniferjuice):
@triciaal help here?
OpenStudy (triciaal):
for f(1) you got 3 for f(0) you got 1
using the formula she originally gave f(1) - (f 0)divided by 1-0
it would be (3-1)/1 = 2
OpenStudy (triciaal):
thanks for the medal