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OpenStudy (jenniferjuice):
@Hamoody1996
OpenStudy (jenniferjuice):
help?
OpenStudy (jenniferjuice):
@IMStuck pleasse helpme out here?
OpenStudy (imstuck):
I will help you! I'm here!
OpenStudy (imstuck):
The trick here is to deal with the numerator and the denominator one at a time. First factor the numerator. I would take a 3 out of all the terms first to make it easier to handle the numbers. Like this...
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OpenStudy (imstuck):
This is just the numerator: \[3(x ^{2}+7x-18)\]Can you factor that?
OpenStudy (jenniferjuice):
3x^2 + 21x - 54
OpenStudy (imstuck):
No...I mean factor it into (x + )(x - )...
OpenStudy (jenniferjuice):
how do 9factor itt?
OpenStudy (imstuck):
Like this:
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OpenStudy (imstuck):
\[3(x+9)(x-2)\]When you multiply all that back out you will get what you started with. Now let's do the denominator.
OpenStudy (imstuck):
That will factor into (x + 9)(x - 6). So what we are left with is this:
OpenStudy (imstuck):
\[\frac{ 3(x+9)(x-2) }{ (x+9)(x-6) }\]
OpenStudy (imstuck):
Between the numerator and the denominator you can cancel out the (x + 9) terms because they are identical and that leaves as your final answer:
OpenStudy (imstuck):
\[\frac{ 3(x-2) }{ (x-6) }\]
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