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Mathematics 17 Online
OpenStudy (jenniferjuice):

http://assets.openstudy.com/updates/attachments/53b4adf2e4b072c759d864a0-jenniferjuice-1404350741321-gs.png

OpenStudy (jenniferjuice):

@Hamoody1996

OpenStudy (jenniferjuice):

help?

OpenStudy (jenniferjuice):

@IMStuck pleasse helpme out here?

OpenStudy (imstuck):

I will help you! I'm here!

OpenStudy (imstuck):

The trick here is to deal with the numerator and the denominator one at a time. First factor the numerator. I would take a 3 out of all the terms first to make it easier to handle the numbers. Like this...

OpenStudy (imstuck):

This is just the numerator: \[3(x ^{2}+7x-18)\]Can you factor that?

OpenStudy (jenniferjuice):

3x^2 + 21x - 54

OpenStudy (imstuck):

No...I mean factor it into (x + )(x - )...

OpenStudy (jenniferjuice):

how do 9factor itt?

OpenStudy (imstuck):

Like this:

OpenStudy (imstuck):

\[3(x+9)(x-2)\]When you multiply all that back out you will get what you started with. Now let's do the denominator.

OpenStudy (imstuck):

That will factor into (x + 9)(x - 6). So what we are left with is this:

OpenStudy (imstuck):

\[\frac{ 3(x+9)(x-2) }{ (x+9)(x-6) }\]

OpenStudy (imstuck):

Between the numerator and the denominator you can cancel out the (x + 9) terms because they are identical and that leaves as your final answer:

OpenStudy (imstuck):

\[\frac{ 3(x-2) }{ (x-6) }\]

OpenStudy (imstuck):

That's it! All done!

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