Question

If the outliers are not included, what is the mean of the data set?

76, 79, 80, 82, 50, 78, 83, 79, 81, 82

77

78

79

80

Answer 1

@Whitemonsterbunny17

Answer 2

First, order them from least to greatest.

Answer 3

Next, think carefully about HOW you will determine which of these data points is/are outlier(s). Are you familiar with "five number summaries?" with box plots? Box plots are the way I'd go were I trying to determine whether or not I have one or more outliers.

Answer 4

50, 76, 78, 79, 79, 80, 81, 82, 83 Correct?

Answer 5

Even without doing a 5-number summary, or box plot, can you spot any outlier? What makes you suspect it's an outlier?

Answer 6

Well 50 seems like an outlier. It is relatively far

Answer 7

Am I right? Anyone?

Answer 8

Yes, I'd agree.

Answer 9

Okay whats next

Answer 10

Look through the numbers to see if you can find any more outliers.. Do you see any more?

Answer 11

you should have a mathematical procedure to detect possible outliers

Answer 12

Um. No outliers I think

Answer 13

There is a method to detect outliers @Zarkon

Answer 14

79.88 is the answer. all you do is add up the numbers and divide by the amount of numbers

Answer 15

Just by eyeballing the data, seeing that 50 is so far removed from the next data point, I'd call 50 an outlier. Notice that I did as you, Gabe, whether you had already learned the "5-number summary" for data, and whether or not you're familiar with the box plot.
Both (but especially the 5-number summary) would enable you to "detect outliers" and thus to satisfy Zarkon.

So, again, are you, Gabe, familiar with the 5-number summary?

Answer 16

@Twix47 please don't give out direct answers, as it is against the CoC (Code of Conduct).

Answer 17

If the outliers are not included, what is the mean of the data set?
1) We have to determine, first of all, whether or not 50 is an outlier. If 50 and/or any other data point is an outlier, then we remove it/them.
2) Only then do we calculate the mean of the (remaining) data.

Answer 18

Okay 50 is an outlier. So we just calculate?

Answer 19

so many people........never so many........

Answer 20

@Gabebro13 : OpenStudy tells me that you're apparently trying to help someone else solve that person's problem. You are, of course, free to pay attention to solving your own math problem or to focus on someone else's; I do that all the time. But be aware that your absence creates a poor impression.

For the third time, Gabe: Have you had any experience with the 5-number summary?

Answer 21

Sorry, short attention span. And no never have I heard of 5-number summary

Answer 22

All right. So be it. With due apologies to Zarkon, we will assume that 50 is an outlier. How many data points are there without that 50?

Answer 23

8

Answer 24

I count 9, even without that 50.

Answer 25

Are you sure? I only see 8. Could you post them?

Answer 26

Maybe we'd better go back to the original problem (which you posted).

Answer 27

An outlier is an observation:
a) above Upper Quartile + 1.5 * Interquartile Range
b) below Lower Quartile - 1.5 * Interquartile Range

Answer 28

@kropot72: are you dissatisfied with my explanations so far? if not, mind stepping in a bit later? Thank you.

Answer 29

Usually you'll do the 5 number summary first, then the IQR rule.

Answer 30

Okay all these people here is starting to freak me out.

Answer 31

no 5 summary for me

Answer 32

To identify outliers, we
c) work out the UQ, LQ and IQR
d) evaluate UQ + 1.5 * IQR and LQ - 1.5 * IQR
e) data values greater than the first or less than the second of these two values are outliers.

Answer 33

I agree: too many cooks spoil the soup. Too many tutors can mess up one's learning process. For the time being I'm going to back out, but will remain in the background as the rest of you hash out a way to address this situation so that Gabe can feel more comfortable.

But before I leave: Please note that there are 10 data points: 76, 79, 80, 82, 50, 78, 83, 79, 81, 82, and that if we remove the only suspected outlier, 50, we have 9 data points left (not 8).

Until later. Good luck!

Answer 34

@mathmate It is obvious by inspection in this case that there is only the one outlier. I apologize for my presenting a way of making sure of outlier identification.

Answer 35

Ignore 50. Add the remaining 9 numbers and divide it by 9.

Answer 36

Thanks guys! It really helped. And I got the answer right!

Answer 37

No apologies needed here. To master this material, one must, unfortunately, master the idea of 5-number summary and then the process of determining whether there are or are not outliers. @Gabebro13 : Good for you!

Answer 38

Don't forget to close the question. @Gabebro13

And also, thanks for using OpenStudy!! *^o^*

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