A can in the shape of a cylinder is to have a combined height and circumference of no more than 108 inches to limit shipping costs. Find the dimensions of the can with maximum volum
is 108 inches an initial volume..?
maximum volume rather..
thats what i think, like its 108 dv/dt=3/4pi(r)^3dr/dt, is that right
u got the wrong formula for the volume of the culinder.. its pi r^2h only..
oh i was thinking sphere
so then it would be 108dv/dt=pi(r)^2(h)dr/dt ?
wait im checking my notes about that problem...
ok
I would just maximize it by looking at the critical points on the derivative, I think.
its a cylinder, not a graph, and the only thing that looks like a derivative is r^2
?
hello
i think 108 is just a perimeter of the cylinder..
i mean that is on the problem i think now it might be optimization
sorry, ok so max volume, if you take the function for volume and take the derivative then find the critical points and determine where the max would be I think it would work
can you so step by step really confused with this one
Sorry I need sleep but this should help http://mathcentral.uregina.ca/QQ/database/QQ.09.09/h/haris1.html
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