An object which is vertically projected or falls from the sky has a velocity of 'v' and is given by: v = -32t + vo, where 'v' is the velocity in feet/sec, 't' is the time in seconds, and 'vo' is the initial velocity in feet per second. If the initial velocity is 300 feet/sec, and the velocity v is in the range of 44 < v < 76, find the time interval t.
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ganeshie8 (ganeshie8):
what we're given ?
what we're asked to find out ?
OpenStudy (anonymous):
v = -32t + vo is given
OpenStudy (anonymous):
initial velocity is 300 feet/sec
ganeshie8 (ganeshie8):
yes, so plug that in
OpenStudy (anonymous):
the time interval t.
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ganeshie8 (ganeshie8):
v = -32t + 300
OpenStudy (anonymous):
divide?
ganeshie8 (ganeshie8):
44 < v < 76
so
44 < -32t + 300 < 76
ganeshie8 (ganeshie8):
first subtract 300 through out
ganeshie8 (ganeshie8):
44 < -32t + 300 < 76
-300 - 300 -300
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OpenStudy (anonymous):
ok so the answer would be (7,8)?
ganeshie8 (ganeshie8):
Yep !
OpenStudy (anonymous):
ok :) good getting it
ganeshie8 (ganeshie8):
I can see that you're a fast learner :) good job, keep it up !!
OpenStudy (anonymous):
thanks yea its an online math class my last one for nursing
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ganeshie8 (ganeshie8):
wow! nice, you must be very excited...
OpenStudy (anonymous):
yes I am
OpenStudy (anonymous):
Im going into a nursing program soon I need this course for my human anatomy
ganeshie8 (ganeshie8):
Oh I got you :) how many years would that program be ?
OpenStudy (anonymous):
2
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