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Use the given information to find the exact value of the expression. sin α = 21/29, α lies in quadrant II, and cos β = 15/17 , β lies in quadrant I Find sin (α - β)
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@satellite73
@ganeshie8
draw a triangle, label the sides
|dw:1404393175079:dw|
Thank you
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then you need \(\cos(\alpha)\) which you find via pythagoras
I got 475/493
you mean as a final answer?
i didn't get anywhere near there yet i am still at \[\cos(\alpha)=-\frac{20}{29}\]
yes
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Hints: 1) You're going to need the "difference formula," sin (a-b) = sin a cos b -cos a sin b. 2) From the given info, you're going to need to find \[\cos \alpha~and ~\sin \beta \]
I'd suggest you begin with (2) and then focus on (1).
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