Is sin(α+2π /3) equal to sin(-α+π/3)? HOW?
Try expanding using: sin (A+B)=sinA cosB = cosA sinB
sorry, the second = sign should be read as +
I am getting confused with the signs while expanding........ But the terms are equal in both......
what did you get?
SinAcos120+cosAsin120 and - sinAcos120-cosAsin120
LHS is correct. But the RHS should be sin(-A)cos60+cos(-A)sin60
You don't need to expand it. Actually \[\sin \theta = \sin (180 - \theta)\] Right ? @bajji
Ya? @ShailKumar
So, put \[ \theta = \alpha + \frac{2\pi}{3}\]
How dos that help the problem.... I did put but the result is sin((540-alpha+2)/3)
Sorry 3alpha.... And if i do the same for the next... It is not equal right?
Actually \[ 180^o = \pi \ rad\] So \[180^o - (\alpha+2\pi/3) = \pi - (\alpha+2\pi/3) = (-\alpha + \pi /3 )\]
Does this help now ?
Ya..... Great! Both are equal......
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