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Mathematics 7 Online
OpenStudy (anonymous):

WILL AWARD MEDAL AND FAN! Can someone please explain step by step how to solve this? This is using double and half angle identities.

OpenStudy (anonymous):

OpenStudy (imstuck):

Ok, this is going to use the half-angle identity for tangent, which is this:

OpenStudy (imstuck):

\[\tan \frac{ A }{ 2 }=\frac{ 1-\cos(A) }{ \sin(A) }\]

OpenStudy (imstuck):

In order to find the sin of A we have to set up the triangle in QII, like this:

OpenStudy (imstuck):

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OpenStudy (imstuck):

So the sin of the angle is 3/5.

OpenStudy (imstuck):

So we can effectively fill in our half-angle formula for tangent now!

OpenStudy (kagıtucak):

cosA=2cos^2(A/2)-1 from half angle identity. -4/5=2cos^2(A/2)-1 2cos^2(A/2)=1/5 cos^2(A/2)=1/10 cos(A/2)=root 1/10 tan(A/2)=sin(A/2)/cos(A/2) =(3/root 10)/(1/root 10) =3

OpenStudy (imstuck):

\[\tan \frac{ A }{ 2 }=\frac{ 1-(\frac{ -4 }{ 5 }) }{ \frac{ 3 }{ 5 } }\]

OpenStudy (imstuck):

Doing that math gives us:

OpenStudy (imstuck):

\[\frac{ \frac{ 5 }{ 5 } +\frac{ 4 }{ 5 }}{ \frac{ 3 }{ 5 } }\]

OpenStudy (imstuck):

\[\frac{ \frac{ 9 }{ 5 } }{ \frac{ 3 }{ 5 } }\]is the same thing as:

OpenStudy (imstuck):

\[\frac{ 9 }{ 5 }\times \frac{ 5 }{ 3 }\]The 5's will cancel and 9/3 = 3.

OpenStudy (anonymous):

Ok thanks for explaining that in detail

OpenStudy (imstuck):

You're welcome! Do you have any more of these!? TY for the medal and fan!

OpenStudy (imstuck):

Oops...I actually have to go to work now! Wow! Time flies when you're having fun! I'll be back on later tonight!

OpenStudy (anonymous):

Ok :)

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