WILL AWARD MEDAL AND FAN! Can someone please explain step by step how to solve this? This is using double and half angle identities.
Ok, this is going to use the half-angle identity for tangent, which is this:
\[\tan \frac{ A }{ 2 }=\frac{ 1-\cos(A) }{ \sin(A) }\]
In order to find the sin of A we have to set up the triangle in QII, like this:
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So the sin of the angle is 3/5.
So we can effectively fill in our half-angle formula for tangent now!
cosA=2cos^2(A/2)-1 from half angle identity. -4/5=2cos^2(A/2)-1 2cos^2(A/2)=1/5 cos^2(A/2)=1/10 cos(A/2)=root 1/10 tan(A/2)=sin(A/2)/cos(A/2) =(3/root 10)/(1/root 10) =3
\[\tan \frac{ A }{ 2 }=\frac{ 1-(\frac{ -4 }{ 5 }) }{ \frac{ 3 }{ 5 } }\]
Doing that math gives us:
\[\frac{ \frac{ 5 }{ 5 } +\frac{ 4 }{ 5 }}{ \frac{ 3 }{ 5 } }\]
\[\frac{ \frac{ 9 }{ 5 } }{ \frac{ 3 }{ 5 } }\]is the same thing as:
\[\frac{ 9 }{ 5 }\times \frac{ 5 }{ 3 }\]The 5's will cancel and 9/3 = 3.
Ok thanks for explaining that in detail
You're welcome! Do you have any more of these!? TY for the medal and fan!
Oops...I actually have to go to work now! Wow! Time flies when you're having fun! I'll be back on later tonight!
Ok :)
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