Question

For f(x)=2x+1 and g(x)=x^2-7, find (f-g)(x)

Answer 1

any thoughts already?

Answer 2

I thinkthat It might be -x^2+2x-6 and it is one of the answer choices

Answer 3

the answer choices are a) x^2-2x-8
b.)2x^2-15
c.)-x2+2x-6
d.)8+2x-12x

Answer 4

OK but why -6? isn't it 8?

Answer 5

sorry my laptop is buggy and so are you saying that it is a?

Answer 6

\(\bf f(x)=2x+1 \qquad g(x)=x^2-7
\\ \quad \\
(f-g)(x)\to f(x)-g(x)\to (2x+1)-(x^2-7)\)

Answer 7

ok so I did that and I got the letter choice c unless I did something wrong

Answer 8

Is \(g=x^2+7\)?

Answer 9

\(\bf f(x)=2x+1 \qquad g(x)=x^2-7
\\ \quad \\
(f-g)(x)\to f(x)-g(x)\to (2x+1)-(x^2-7)
\\ \quad \\
\to 2x+1{\color{brown}{ -x^2+7}}\to -x^2+2x-8\)

Answer 10

hhmm \(\bf f(x)=2x+1 \qquad g(x)=x^2-7
\\ \quad \\
(f-g)(x)\to f(x)-g(x)\to (2x+1)-(x^2-7)
\\ \quad \\
\to 2x+1{\color{brown}{ -x^2+7}}\to -x^2+2x+8\) rather

Answer 11

anyhow.. the -() in front of g(x) turns all signs the other way, thus

Answer 12

so the answer is D

Answer 13

hmm I'd think you have a typo on D, so... I guess so =)

Answer 14

thank you :D

Answer 15

yw