A parabola has directrix y=-3, axis x=4 and latus rectum equal to 2. Find its equation. pls help :)
i can yes ... do you recall what a latus rectum is?
uhmm. its a chord that passes through the focus? hahaha.. im not that sure though. :D
youre right actually :) i have an idea on how to do this
lets create a parabola that fits, then move it into place
ok. :)
this distance between focus and directrix should be 6 ... so lets have a parabola of vertex 0,-3 with roots of -1,0 and 1,0 this gives us a width of 2 at the focus
so.... f(x) = a(-1-x)(1-x), such that f(0) = -3 -3 = a(-1)(1), a=3 our parabola to move is therefore f(x) = 3(-1-x)(1-x) , but how to move it?
we need to raise it by 3, and move it to the right by 4
so the alterations are: f(x) = 3(-1-(x-4))(1-(x-4)) + 3 and from that we can simplify it to our hearts content
ohh because of axis x=4?
yes, and i have to review my setup since i evidently got something off along the way
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