i need help
Point A is located at (1, 5), and D is located at (−3, 7). Find the coordinates of the point that lies halfway between A and D. (−3, 4) (−1, 6) (1, 6) (3, 4)
@wio
D
i don't want the answer i want to know how to do it
ok
can you teach me?
@iPwnBunnies
\(\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ A&({\color{red}{ 1}}\quad ,&{\color{blue}{ 5}})\quad D&({\color{red}{ -3}}\quad ,&{\color{blue}{ 7}}) \end{array}\qquad \left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right)\)
if you don't know how to do it then how do you know its D?
is that the slope formula
nope, "midpoint formula"
i got -2.5 and 9.5
hmmm let's see \(\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ A&({\color{red}{ 1}}\quad ,&{\color{blue}{ 5}})\quad D&({\color{red}{ -3}}\quad ,&{\color{blue}{ 7}}) \end{array}\qquad \left(\cfrac{{\color{red}{ -3}} + {\color{red}{ 1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ 7}} + {\color{blue}{ 1}}}{2} \right)\\ \quad \\\implies \left(\cfrac{-2}{2}\quad ,\quad \cfrac{9}{2}\right)\implies \left(-1\quad ,\quad 4\frac{1}{2}\right)\)
hmmm whwat the hold the mayo. lemme fix that
\(\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ A&({\color{red}{ 1}}\quad ,&{\color{blue}{ 5}})\quad D&({\color{red}{ -3}}\quad ,&{\color{blue}{ 7}}) \end{array}\qquad \left(\cfrac{{\color{red}{ -3}} + {\color{red}{ 1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ 7}} + {\color{blue}{ 5}}}{2} \right) \\ \quad \\ \left(\cfrac{-2}{2}\quad ,\quad \cfrac{12}{2}\right)\implies (-1\quad ,\quad 6)\)
oh thank you
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