Question

Two tuning forks exhibit beats at a beat frequency of 3Hz.The freq of one fork is 256Hz.Its freq is then lowered slightly by adding a bit of wax to one of its prong.The two forks then exhibit a beat freq of 1Hz.Determine the freq of 2nd tuning fork.

Answer 1

@Abhisar

Answer 2

the frequency of the 2nd tuning fork may be 259 Hz or 253 Hz
now after adding a bit of wax the frequency of 1st tuning fork become lower than 256 Hz
that means the FREQUENCY OF 2ND TUNING FORK MUST BE 253 Hz.

Answer 3

@Abhisar

Answer 4

Since the beat frequency went from 3 to 1, the wax decreased the difference between the 2 forks. Since lowering the frequency of the 1st fork brought that fork's frequency closer to that of the 2nd, the 2nd fork's frequency must be less than 256 Hz.

The 2nd fork's frequency was less than 256 Hz and because the original beat frequency was 3 Hz, says that the difference was 3 Hz. So the 2nd fork's frequency is 253 Hz.

Answer 5

ok thanks

Answer 6

No problem