Write the polynomial in simplest form with roots 4, 5i, and -5i.
Take the complex roots first. You just need one root because complex roots always occur in pairs. x = 5i square both sides: x^2 = (5i)^2 = -25 (x^2 + 25) = 0 will have the roots 5i and -5i Now multiply (x^2 + 25) by (x-4) to get the polynomial.
since the roots are 4, 5i, and -5i. the polynomial is of the form (x-4)(x+5i)(x-5i)
Thank you!
You are welcome.
Could you possilbly do another example? I dont really understand it
Well, another way to do the same problem is what matricked suggested above. If three roots, a, b and c are given, then the simplest polynomial with those three roots is: (x-a)(x-b)(x-c). So here it is (x+5i)(x-5i)(x-4) First multiply (x+5i)(x-5i). Use the identity (a+b)(a-b) = a^2 - b^2 So (x+5i)(x-5i) = x^2 - (5i)^2 = x^2 + 25 Then multiply (x^2+25)(x-4)
Like foils, thank you! is this for all polynomial things, no matter what roots are given?
Yes. If they given you any number of roots and ask for the simplest polynomial with those roots, then just proceed as shown. This works because if 'a' is a root it implies (x-a) is a factor.
So if a, b, c, d, e are roots then (x-a), (x-b), (x-c), (x-d), (x-e) are factors and you can multiply them all and find the polynomial. Example find the simplest polynomial with roots 2 and -3. Answer: (x-2)(x- -3) or (x-2)(x+3). FOIL it and simplify to get x^2 + x - 6.
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