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Mathematics 20 Online
OpenStudy (anonymous):

Use the product rule to find the derivative....

OpenStudy (anonymous):

\[(x+1)(\sqrt{x} +2)\] how would I deal with the radical in this case? \[x^{1/2}\] ???

OpenStudy (anonymous):

Yes

OpenStudy (sheraz12345):

Multiply x with underrroot x which will give x^3/2

zepdrix (zepdrix):

No don't multiply. That defeats the purpose of applying the product rule.

OpenStudy (anonymous):

Product Rule: \[U \times V'+ U' \times V\]

OpenStudy (anonymous):

product rule is.. \[(ab)\prime=a \prime b+ab \prime\] then here.. {(x+1)(√x+2)}'=1(√x+2)+(x+1)*1/2x^-1/2

OpenStudy (anonymous):

More formally. \[f(x) \times g'(x)+f '(x) \times g(x)\]

OpenStudy (anonymous):

You can treat the 1/2 like any other exponent. So if you are taking the derivative of that. \[nX^{n-1}\] Where in your case n would be 1/2

OpenStudy (anonymous):

You would first multiply the original first expression by the derivative of the second expression then add the derivative of the first expression multiplied by the original second.

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