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Let m be a positive integer. Show that a mod m = b mod m if a ≡ b (mod m). Use only the definitions of mod m and congruence modulo m; do not use any theorems involving mod or congruence.
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use the definition
\(a \equiv b \mod m\) means \(m | (a-b)\)
\(\large \implies a-b = mk\)
\(\large a = mk +b\) substitute this value in the left side of congruence you wanted to prove
\(\large a \mod m = (mk + b) \mod m \equiv b \mod m\) QED.
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Hare Ganesh!
let me know if something is not clear :)
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