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Find the least common multiple of x^3 - x^2 + x - 1 and x^2 - 1. Write the answer in factored form. A. (x+1)^2(x-1) B.(x+1)(x-1)(x^2+1) C.(x^3-x^2+x-1)(x^2-1) D.(x+1)(x-1)(x^2-1)
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It's B.
Factor first the \[x ^{3}-x ^{2}+x-1\]by grouping. Like this:
\[(x ^{3}-x ^{2})+(x-1)\]
Factor the first set of parenthesis like this:
\[x ^{2}(x-1)\]and you still have the + (x - 1), so actually what you have is this:
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\[x ^{2}(x-1)+(x-1)\]You can factor that further by taking out an (x - 1), like this:
\[(x-1)[x ^{2}+1]\]
That's the factorization of the third degree polynomial. The other one goes like this, and much simpler:\[(x ^{2}-1)=(x+1)(x-1)\]
So you have (x+1)(x-1)(x^2+1). See?
Yeah thanks :)
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