Question

y=x(c-x) where c is a constant , find the maximum value of y

Answer 1

@RadEn

Answer 2

y=cx-x^2
\[\Large \frac{dy}{dx}=c-2x=0 = > x = \frac{c}{2}\]
\[\Large \frac{d^2y}{dx^2}= -2 (<0)\]
i.e maxima ..at x=c/2 which is
\[\Huge y=\frac{c}{2}(c-\frac{c}{2})\]

Answer 3

Oh, i got it thanks

Answer 4

tada