Determine which system below will produce infinitely many solutions. A. -6x+3y=18 4x-3y=6 B. 2x+4y=24 6x+12y=36 C. 3x-y=14 -9x+3y=-42 D. 5x+2y=13 -x+4y=-6 i really need help @jigglypuff2
@Hero
i think its C
@SkiTTleoooo47 can you help me please??
@jim_thompson5910 will you help me please?
is C a random guess or do you have something to back you up on why you think it's C?
a random guess I'm not good at this at all can you please teach me?
one good way to go about this is to graph each system
I'd use https://www.desmos.com/calculator if you don't have a graphing calculator
how does it let you know how many solutions it can produce?
each equation generates a line, so you'll have 2 lines (2 equations ---> 2 lines) where the two lines cross is where the solution is
if you get 2 parallel lines, then there are NO solutions if you have one line lie completely and perfectly on top of the other, then you get infinitely many solutions
how many times it crosses with each other will let you know how many solutions there are right?
correct, with a system of linear equations, there are only these scenarios A) exactly one solution (one intersection point) B) NO solutions at all (with parallel lines never crossing) C) infinitely many solutions (one line lies completely and perfectly on top of the other)
oh ok but don't i have to y=mx+b? or something to get a slope
you can convert each equation into slope intercept form but luckily the graphing calculator I posted above lets you type in any equation of any form (and it will graph it)
oh really? so it'll graph it and then what do i do?
A is no solution so it can't be that right?
here's what we get when we graph the system in choice A notice the colors: the red line is the first graph -6x+3y=18 the blue line is the second graph 4x-3y=6
In the image of the graph, we see that the two lines are NOT parallel so they cross somewhere they cross at (-12,-18) which is the solution to the system of equations this is the only solution to this system of equations
oh ok i did that one wrong I'm still trying to get the hang of this calculator but B is no solution
Is A the answer?
look back at the instructions "Determine which system below will produce infinitely many solutions."
ok so A produces one and B does not so far right?
correct, A has one solution B has none
so neither are the answer
it's either C or D
For c i got 2 solutions?
how did you get 2 solutions?
it had 2 points on the line.
it only had 1 line and 2 points on it
did you graph both equations?
yes i think its D is that correct?
how many solutions does D have?
3? and oh yeah i graphed C wrong i put only one equation sorry
with a system of linear equations, there are only these scenarios A) exactly one solution (one intersection point) B) NO solutions at all (with parallel lines never crossing) C) infinitely many solutions (one line lies completely and perfectly on top of the other)
on C and D I'm confused
can you post a screenshot of what you got when you graphed system D
I want to see what you're getting
ill try
this is what i got?
ok I see now, thanks notice how the two lines (the purple and orange) cross at exactly one point so there is exactly one solution
by the way, I recommend zooming in to better see the solution point
so that rules out choice D since D has exactly one solution
Ok there were three points like ordered pairs when i zoomed in on one what does that mean?
3 points?
yes
oh those other two points you're able to click on are the x-intercept and y-intercept
these points (x-intercept and y-intercept) are where the line crosses the x and y axis
what we care about is where the two lines cross (ignore the axis)
ok should i show you what i got for c?
sure go for it
oh wait its C right? because i typed in both equations and it overlapped completely
correct, you can turn one equation on and off to see it blinking on top of the other
the perfect match means there are infinitely many intersections ----> infinitely many solutions
ok I'm new on this site so thank you soo zoo much for your help and taking your time to help me! :)
soo*
you're welcome and welcome to the OpenStudy
thanks
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