Question

b^2 + 2b + 1 factored ?

Answer 1

You are wanting to factor this?

Answer 2

i got that one i need a new one now, can you help me factor a^2 - a -6

Answer 3

(b+1)(b+1) or (b+1)^2, it is also called a perfect square I believe.

Answer 4

Yes !! thats what i got :)

Answer 5

a^2 - a - 6

(a-3)(a+2)

Answer 6

Do you want some help so you know how to figure them out on your own?

Answer 7

I can teach you basic factoring methods...

Answer 8

yes please could you show me on this one n^2 + 8n - 9

Answer 9

Well how I would show you basic factoring is a little different than starting with this specific example, but it seems you are needing help with homework so,

n^2 + 8n - 9 -> (n+9)(n-1)

Answer 10

Always look at your last component which is C in your standard form (Ax^2+Bx+C) of a linear equation. Ask yourself, what two #'s do I multiply to get this number?
In the case of 9 previous, we can do 9*1, 3*3, and that's it.

Answer 11

Standard form actually includes Ax^2+Bx+C=0.

Answer 12

okay well i need those to find out common denominators. i know how to do the reallllly simple ones but i just dont think hard enough for those so i need the answers quick and easy. the other one was n^2 - 1 so i just need to combine like terms

Answer 13

so (n-1) (n+1) ( n+9) (n-1)

Answer 14

and combine it

Answer 15

n^2-1 is a difference of squares,

(n-1)(n+1)

Answer 16

and what would it look like if i combined it ?

Answer 17

Sorry, not a difference of squares... not sure.

If you combined (n-1)(n+1) and ( n+9) (n-1)?

Answer 18

yes!!

Answer 19

would it be like (n-1) (n+1) (n+9) ?

Answer 20

You would come to a 4th degree polynomial. What is the problem asking exactly?

Answer 21

" find at least common denominator for these two rational expressions"

Answer 22

okay well the answer is (n-1) (n+1) (n+9) !!

Answer 23

okay new one a^2 - 2a - 15

Answer 24

(a-5)(a+3)

Answer 25

Ok so a better answer is,

Ask yourself which two numbers multiply to 15 that when you take the difference will = -2, which is your B component. You ask yourself the "difference" question when you have two (-)'s in your polynomial.

Answer 26

3 and 5 multiply to 15, and 5-3 = 2

Answer 27

Since B is negative, or B=-2, you make the larger number (5), the negative part (a-5)

Answer 28

The A, B, C numbers, B and C in particular, are the Ax^2 + (B)x + (C) in your form.
a^2 - 2a - 15 where A=1, B =-2, and C = -15, are you seeing what I'm saying?

Answer 29

3x^2+4x+15 has A=3, B=4, and C=15
This is not factor-able so don't worry.

when you have x^2, or any number ^2 without a leading coefficient, x^2, a^2, c^2...
Your A=1. So x^2 +2x+1, A=1, B=2, and C=1

Answer 30

Leading coefficient refers to the number before the x, a, or whatever is the first part. x^2, 2x^2, 3x^2: Your leading coefficient is 1, 2, and 3; or A= 1, 2, and 3

Answer 31

So in your case your dealing with just the integer 1 as your leading coefficient for these polynomials you are needing to facvor.

Answer 32

A=1, so we are not concerned with A at all. If your equation is +, +, or B and C are both positive: Ex. x^2 +2x+1, then your factors become (x+something)(x+something)

Answer 33

Am I helping you at all?