Question

2^x*2^(2x+1)=128
Solve equation.

Answer 1

\[2^x*2^{2x+1}=128\\2^x*2^{2x}*2^1=128\\2^x*2^{2x}=64\\2^{x+2x}=64\\2^{3x}=2^6\\3x=6\\x=2\]

Answer 2

Do you how to solve the problem using logarithms and thank you for your help

Answer 3

do you wanna solve this by logarithm?

Answer 4

yes

Answer 5

\[2^{x}*2^{2x+1}=128\\ \log_{2}\\ \log_{2}2^{x+2x+1}=\log_{2}128\\log_{2}2^{3x+1}=\log_{2}2^7 \]

Answer 6

so
now
3x+1=7

Answer 7

\[(3x+1)\log_{2}2=7\log_{2}2\\log_{2}2=1\\3x+1=7\]

Answer 8

Thank you so much @amoodarya