Question

What is the component of (3i + 4j) along (i+j) ?

Answer 1

@hartnn

Answer 2

@ganeshie8

Answer 3

@jim_thompson5910

Answer 4

component of vector A along B is just
\(\Large \dfrac{A.B}{|B|}\)

Answer 5

its actually \( |A| \cos \theta \)
but we know form the definition of dot product that
\(A.B = |A||B| \cos \theta \)

Answer 6

ok here it is already in vector form, so i did it like this,
(3i + 4j).(i+j)= 3+4=7

Answer 7

right, thats your numerator

Answer 8

and now magnitude of (i+j) = root 2

Answer 9

so answer should be

Answer 10

??

Answer 11

that is correct :)

Answer 12

but it's not the answer which i should get !
\(\color{green}{\huge\ddot\frown}\)

Answer 13

whats the answer that u should get ?

Answer 14

I think component means vector projection. The formula we used is for scalar projection.