Mathematics
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OpenStudy (anonymous):
Fifty students in the fourth grade class listed their hair and eye colors in the table below:
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OpenStudy (anonymous):
Are the events "green eyes" and "brown hair" independent?
OpenStudy (anonymous):
Ya
OpenStudy (anonymous):
i have no clue :/
OpenStudy (zarkon):
two events A and B are independent iff
\[P(A\cap B)=P(A)P(B)\]
so does...
P(green eyes and brown hair)=P(green eyes)*P(brown hair)?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
wait no?
OpenStudy (zarkon):
really...show the work based on the data given
OpenStudy (anonymous):
im really sorry i suck at stats
OpenStudy (zarkon):
start with P(green eyes)=#green eyes/total number people
OpenStudy (anonymous):
so 28/50?
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OpenStudy (zarkon):
yes
now what is the prob of brown hair
OpenStudy (anonymous):
30/50?
OpenStudy (zarkon):
yep
OpenStudy (zarkon):
what is the p( green eyes and brown hair)
OpenStudy (anonymous):
16/50???
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OpenStudy (zarkon):
yes
OpenStudy (zarkon):
so is this true...
P(green eyes and brown hair)=P(green eyes)*P(brown hair)?
OpenStudy (anonymous):
so are they independent? i dont understand tht part
OpenStudy (zarkon):
answer my question
is this true...
P(green eyes and brown hair)=P(green eyes)*P(brown hair)?
OpenStudy (anonymous):
no it is not
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OpenStudy (zarkon):
correct...therefore the events are not independent...they are dependent
OpenStudy (anonymous):
yay thank you