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Mathematics 20 Online
OpenStudy (anonymous):

Fifty students in the fourth grade class listed their hair and eye colors in the table below:

OpenStudy (anonymous):

Are the events "green eyes" and "brown hair" independent?

OpenStudy (anonymous):

Ya

OpenStudy (anonymous):

i have no clue :/

OpenStudy (zarkon):

two events A and B are independent iff \[P(A\cap B)=P(A)P(B)\] so does... P(green eyes and brown hair)=P(green eyes)*P(brown hair)?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

wait no?

OpenStudy (zarkon):

really...show the work based on the data given

OpenStudy (anonymous):

im really sorry i suck at stats

OpenStudy (zarkon):

start with P(green eyes)=#green eyes/total number people

OpenStudy (anonymous):

so 28/50?

OpenStudy (zarkon):

yes now what is the prob of brown hair

OpenStudy (anonymous):

30/50?

OpenStudy (zarkon):

yep

OpenStudy (zarkon):

what is the p( green eyes and brown hair)

OpenStudy (anonymous):

16/50???

OpenStudy (zarkon):

yes

OpenStudy (zarkon):

so is this true... P(green eyes and brown hair)=P(green eyes)*P(brown hair)?

OpenStudy (anonymous):

so are they independent? i dont understand tht part

OpenStudy (zarkon):

answer my question is this true... P(green eyes and brown hair)=P(green eyes)*P(brown hair)?

OpenStudy (anonymous):

no it is not

OpenStudy (zarkon):

correct...therefore the events are not independent...they are dependent

OpenStudy (anonymous):

yay thank you

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