A board game has a spinner with ten equal sections, numbered 1 through ten. In order to win the game, Mae needs to spin at least a 6 on each of her last two turns. What's the probability of this happening?

one percent

ten percent

twenty-five percent

thirty-six percent

Question

A board game has a spinner with ten equal sections, numbered 1 through ten. In order to win the game, Mae needs to spin at least a 6 on each of her last two turns. What's the probability of this happening?

 one percent

 ten percent

 twenty-five percent

 thirty-six percent

anonymous · Answer

at least a 6 means 6,7,8,9,10 so five out of ten or one half for each try
since she has to do it twice, that would be one half times one half or 
$$\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}$$

anonymous · Answer

so 25%?

anonymous · Answer

yes

mrnood · Answer

@satellite73 
It is discouraged by the code of conduct for this site to give direct answers.

The OP learns nothing from having someone else give them the answer.

Maybe you could've stopped before doing the sum above - your explanation would give the OP a chance to try to do the sum for himself....

anonymous · Answer

@MrNood -_- he is being helpful and he did not even give out a direct answer

anonymous · Answer

what are u gonna do ban him ???? xD he's a mod