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Mathematics 8 Online
OpenStudy (anonymous):

Which choice is equivalent to the product below for acceptable values of x? (is my answer right? question below)

OpenStudy (anonymous):

OpenStudy (imstuck):

Your answer is not correct. As long as the indexes are the same on the radicals, and they are because they are both square roots (as opposed to one being a square root and another being a cubed root, for example) they multiply out exactly the same as they would if there was not a radical sign there. Like this:

OpenStudy (imstuck):

\[\sqrt{5x} * \sqrt{x+3}=\sqrt{5x * (x+3)}\]

OpenStudy (imstuck):

Distribute the 5x into the parenthesis just like you would with a "regular" expression. That equals...

OpenStudy (anonymous):

So, it's A. But then would my answer have to be simplified (the 15) into and 5

OpenStudy (anonymous):

3 and 5*

OpenStudy (imstuck):

If you factored that again while it is under the radical sign as a single expression, you would end up with what you started with, which is 5x(x+3) all under a single radical...which is fine, but it is not a choice. So you need to leave it with an x^2 in the first term. Distribute the 5x into the (x + 3) and what do you get? 5x(x+3) = ?

OpenStudy (anonymous):

Yeah so... it's 5x^2 + 15 (all under the radical of course)

OpenStudy (imstuck):

No, its not because you're forgetting that when you multiply the 5x(3) that's 15x not just 15

OpenStudy (imstuck):

It's not A

OpenStudy (anonymous):

Oh yeah... the x needs to be there. Duh. Then it's C, because when you distribute the 5x the x needs to be there too. :P

OpenStudy (imstuck):

Right! Good job!

OpenStudy (anonymous):

Thank you so much. :)

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