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show that (ku ⃗)∙(v ⃗)=k(u ⃗∙v ⃗) for vectors in two space. Given u ⃗=(x_1,y_1),v ⃗=(x_2,y_2) (ku ⃗)∙(v ⃗)=(k(x_1,y_1))(x_2,y_2) =(kx_1,ky_1)(x_2,y_2) =kx_1 x_2+ky_1 y_2 =k(x_1 x_2+y_1 y_2) =k(u ⃗∙v ⃗)
yes ur correct
To me, you should go on 2 column-proof
@Bebong no need for that lol @cutepochacco u did great ^
I mean |dw:1404605235402:dw| @ikram002p the proof above is weak at line 4 to line 5
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* line5 to line6
O.O IMHO i dnt think so :P but u have ur point of view as well
Linear algebra!!! I hate it!! it beats me up
meh worth two marks.
i just pretty much followed the example from the textbook and changed it from three space to two space
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thank you for the replies
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