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Mathematics 18 Online
OpenStudy (anonymous):

is this right?

OpenStudy (anonymous):

show that (ku ⃗)∙(v ⃗)=k(u ⃗∙v ⃗) for vectors in two space. Given u ⃗=(x_1,y_1),v ⃗=(x_2,y_2) (ku ⃗)∙(v ⃗)=(k(x_1,y_1))(x_2,y_2) =(kx_1,ky_1)(x_2,y_2) =kx_1 x_2+ky_1 y_2 =k(x_1 x_2+y_1 y_2) =k(u ⃗∙v ⃗)

OpenStudy (ikram002p):

yes ur correct

OpenStudy (anonymous):

To me, you should go on 2 column-proof

OpenStudy (ikram002p):

@Bebong no need for that lol @cutepochacco u did great ^

OpenStudy (anonymous):

I mean |dw:1404605235402:dw| @ikram002p the proof above is weak at line 4 to line 5

OpenStudy (anonymous):

* line5 to line6

OpenStudy (ikram002p):

O.O IMHO i dnt think so :P but u have ur point of view as well

OpenStudy (anonymous):

Linear algebra!!! I hate it!! it beats me up

OpenStudy (anonymous):

meh worth two marks.

OpenStudy (anonymous):

i just pretty much followed the example from the textbook and changed it from three space to two space

OpenStudy (anonymous):

thank you for the replies

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