Mathematics
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OpenStudy (jbeanz97):
can someone please help me with an algebra1 question?
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OpenStudy (jbeanz97):
\[if, f(x)=\frac{ 2x }{ 2x+1 } and, g(x)=\frac{ 1 }{ 2x+1 }, find f(x)+g(x)\]
geerky42 (geerky42):
What did you get?
OpenStudy (jbeanz97):
i dont understand how to solve it
geerky42 (geerky42):
You just need to find and simplify f(x)+g(x)
geerky42 (geerky42):
Do you know what f(x) and g(x) are?
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OpenStudy (jbeanz97):
well it says f(x) and g(x) are those fractions, but how do i simplify those fractions?
geerky42 (geerky42):
Well, you have \(\dfrac{2x}{2x+1}+\dfrac{1}{2x+1}\). Do you know what to do next? Note that denominators are same
OpenStudy (jbeanz97):
do we cross cancel?
geerky42 (geerky42):
Say you have like \(\dfrac{2}{5}+\dfrac{3}{5}\) to solve, what will you do?
OpenStudy (jbeanz97):
add the top and bottom?
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OpenStudy (jbeanz97):
so it would give you 4/10?
OpenStudy (jbeanz97):
**5/10
geerky42 (geerky42):
no, it would give you 5/5
when denominator is same, you can add numerators, only numerators.
OpenStudy (jbeanz97):
oohh okay i gotcha
geerky42 (geerky42):
So adding numerator together and you will have \(\dfrac{2x+1}{2x+1}\). make sense?
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OpenStudy (jbeanz97):
yeah!
geerky42 (geerky42):
so what's next?
OpenStudy (jbeanz97):
hmm im not sure :/
geerky42 (geerky42):
you do noticed that numerator and denominator are same?
OpenStudy (jbeanz97):
yeah
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OpenStudy (jbeanz97):
so would it become 1
geerky42 (geerky42):
right! so we have \(\dfrac{\cancel{2x+1}}{\cancel{2x+1}} = \dfrac{1}{1}=\boxed{1}\)
geerky42 (geerky42):
So we have f(x)+g(x)=1
that's your answer. is that clear?
OpenStudy (jbeanz97):
yes that was clear! thanks for the help!! :)
geerky42 (geerky42):
welcome
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OpenStudy (jbeanz97):
could you possibly help me with another question?