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What is the solution to the equation 9 ^3x ≈ 7?
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Is it \[9^{3x}\approx 7\] ?
yes
\[\Huge 9^{3x}\approx 7\] Let us assume it nearly equal. \[\Huge 3x = \log_9 7\] \[\Huge x= \frac{\log_9 7}{3}\]
= \[\Huge \frac{\log 7}{3 \log 9 } = \frac{\log 7}{6 \log 3} \]
x is nearly \(\Huge 0.30\)
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here are the answer choices x = 0.376 x = 0.295 x = −0.295 x = −0.376
You can verify it by \[\Large 9^{3 \times 0.30} = 9 ^{ 0.9 } =7.22 ..\] nearly 7 x is also NEARLY 0.30 (round off..)
0.295 to be exact which I rounded upto 0.30
thank you
uw
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