Question

how do you solve the lim x 4 square root of x-2 divided by x-4

Answer 1

You mean this? \(\large \displaystyle\lim_{x\rightarrow4}\dfrac{\sqrt{x-2}}{x-4}\)

Answer 2

yes

Answer 3

@hartnn

Answer 4

but i think the question is
\(\large \displaystyle\lim_{x\rightarrow4}\dfrac{\sqrt{x}-2}{x-4}\)
is it ?

Answer 5

is -2 in square root or no? @Landva2

Answer 6

its outside

Answer 7

do you know
\(a^2 - b^2 = .. ?\)

Answer 8

\(\Large x-4 = (\sqrt x)^2 - 2^2 = ... ?\)

Answer 9

I am not seeing how that equal 1/4 maybe I am doing something wrong

Answer 10

\(a^2-b^2=(a-b)(a+b)\)

So \((\sqrt x)^2-2^2=\ldots?\)

Answer 11

Do you know what to do? @Landva2
we are trying to "factor" denominator