Question

Need help setting up equation to calculate work for downward-pointing cone. Medal and fan

Answer 1

First let's find the volume of the the oil. The volume of a cone is

V=π×r^2×h/3

and we have given that h=10 and r=5. Also, we know that it's half full, so the volume of
the oil will be

Vo=π×r^2×h/6 = π×5^2×10/6 = 125×π/3

Now we can use that and the density we were given to find the weight of the oil.

Weight=Density×Volume=56×125/3×π=7000/3×π

Now, this is where the tricky part comes in. From physics, the equation for work is

W=F×d

Gravity is constantly going to be exerting a force on the oil to pull it downwards, and so in order to lift it we need to apply a slightly greater force than gravity does. Applying the same force will result in the oil not gaining any velocity at all. So the best I can do is give you the lower bound for the work.

W>Weight×d
W>7000/3×π×3
W>7000π

Answer 2

in the question it says that it is necessary to multiply by the gravitational acceleration constant in order to find the work. also, did you change the h and r values on purpose

Answer 3

i got 4248pi

Answer 4

..not correct