Trigonometry Help Simplify the Expression: ((9cos x)/(sin^2 x))((sin x cos x - 7sin x)/(cos^2 x - 49))
if you cant understand the problem typed out, i attached a picture of it
|dw:1404674356479:dw|
yes, you can cancel out the top sinx and and denominator one becomes just sin x. Then the cos x/ sin x becomes cot x in de numenator
but you can also factor the bottom as (cos x -7) (cos x + 7)...that way you can cancel out the top (cos x -7) and the denominator one
ahh i knew something had to cancel with that 7 and 49
alright lets esee if i can get it now
so the final answer would be
|dw:1404674972712:dw|
correct? or i can go farther?
doesnt look like it ogg (this is stupid, backspace wont work) goes farther
cot x = 1/ tan x... so you can turn it into 9/ tan x (cos x +7)... can you simplify that?
i dont thin so
oh wait, maybe i think i know how
would you do tan x = sin/cos
tan x = sin x/ cos x -> tanx * cos x = sinx -> 9/sin x + 7 tan x... it's not really simpler than the previous version, but in some cases you might use the latter version.
so it would become 9/(sin/cos)(cosx +7)
sorry i sent that before you sent that last message.
you learn to simplify such expressions because when you have to do limits, derivatives and integrals you might want to play around with a simpler version
alright good to know, ill just write down both answers and talk to my professor tomorrow and see which he would prefer as the answer.
i really appreciate that help
No prob :-)
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