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Mathematics 10 Online
OpenStudy (anonymous):

Trigonometry Help Simplify the Expression: ((9cos x)/(sin^2 x))((sin x cos x - 7sin x)/(cos^2 x - 49))

OpenStudy (anonymous):

OpenStudy (anonymous):

if you cant understand the problem typed out, i attached a picture of it

OpenStudy (anonymous):

|dw:1404674356479:dw|

OpenStudy (anonymous):

yes, you can cancel out the top sinx and and denominator one becomes just sin x. Then the cos x/ sin x becomes cot x in de numenator

OpenStudy (anonymous):

but you can also factor the bottom as (cos x -7) (cos x + 7)...that way you can cancel out the top (cos x -7) and the denominator one

OpenStudy (anonymous):

ahh i knew something had to cancel with that 7 and 49

OpenStudy (anonymous):

alright lets esee if i can get it now

OpenStudy (anonymous):

so the final answer would be

OpenStudy (anonymous):

|dw:1404674972712:dw|

OpenStudy (anonymous):

correct? or i can go farther?

OpenStudy (anonymous):

doesnt look like it ogg (this is stupid, backspace wont work) goes farther

OpenStudy (anonymous):

cot x = 1/ tan x... so you can turn it into 9/ tan x (cos x +7)... can you simplify that?

OpenStudy (anonymous):

i dont thin so

OpenStudy (anonymous):

oh wait, maybe i think i know how

OpenStudy (anonymous):

would you do tan x = sin/cos

OpenStudy (anonymous):

tan x = sin x/ cos x -> tanx * cos x = sinx -> 9/sin x + 7 tan x... it's not really simpler than the previous version, but in some cases you might use the latter version.

OpenStudy (anonymous):

so it would become 9/(sin/cos)(cosx +7)

OpenStudy (anonymous):

sorry i sent that before you sent that last message.

OpenStudy (anonymous):

you learn to simplify such expressions because when you have to do limits, derivatives and integrals you might want to play around with a simpler version

OpenStudy (anonymous):

alright good to know, ill just write down both answers and talk to my professor tomorrow and see which he would prefer as the answer.

OpenStudy (anonymous):

i really appreciate that help

OpenStudy (anonymous):

No prob :-)

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