Question

state the domain and range of the following functions. g(x)=sqrt(x+6)

Answer 1

the domain are all the values x can have, the range are all the values g(x) can be. So you have to ask yourself are there any values for x that could make the function unsolvable. What is not allowed with a squareroot? You can't take the squareroot of a negative number. So x can't be lower than? Can x become infinite high? If yes you'll get a domain of [x_min, +infinity[.

Answer 2

so any number that is over 6 and makes it negative can or can't bethe domain?

Answer 3

yes, the domain would be [-6, + infinity[... you can take the square root of 0, because that equals 0.

Answer 4

and for the range?

Answer 5

well ask yourself what the result can't be from a root? What the lowest value the solution of any root can have?