Question

Find the angle between the given vectors to the nearest tenth of a degree.
u = <-5, -4>, v = <-4, -3>

Answer 1

\(\bf \textit{angle between two vectors }\\ \quad \\
cos(\theta)=\cfrac{u \cdot v}{||u||\ ||v||} \implies \cfrac{\text{dot product}}{\text{product of magnitudes}}\\ \quad \\
\theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||\ ||v||}\right)\)

Answer 2

I did that and got 0.99

Answer 3

is that right?

Answer 4

i'll show you my work if you want

Answer 5

hmm what did you get for the dot product?

Answer 6

(-5)(-4) + (-4)(-3) = 20+ 12 = 32

Answer 7

ok.... lemme check

Answer 8

ohhh i think i know what i did

Answer 9

one sec im going to redo it

Answer 10

is it 1.8?

Answer 11

yeap 1.789910 degrees, thus \(\large 1.8^o\)

Answer 12

thanks so much!!! :)

Answer 13

yw