Question

I just want the idea how to do this

Answer 1

\[\frac{ (1+i)x-2i }{ 2+i } + \frac{ (2-3i)y-i }{ 3-i }=i\]

Answer 2

The real values of x and y satisfing this equation

Answer 3

compute the mess on the left
set the real part equal to zero and the imaginary part equal to one

Answer 4

set the real part equal to zero and the imaginary part equal to one?

Answer 5

yes since \(i=0+1i\)

Answer 6

ohhk!!

Answer 7

\[\frac{ (3+2i+1)x -2i +(6-7i +3)y +i }{ 10 }\]

Answer 8

the l.h.s @satellite73

Answer 9

the answer is x= 3, y= -1

Answer 10

No problem thanks for trying!! :)

Answer 11

wait how did you add these?

Answer 12

oh nvm i think it is right sorry