Can anyone help me with these questions?
(I'll put the question's image on the comment)

Question

Can anyone help me with these questions?
(I'll put the question's image on the comment)

anonymous · Answer

attachment

larseighner · Answer

The first one is easy.

Four consecutive odd numbers equal  224, so

o + (o+2) + (o+4) + (o + 6) = 224
4o = 212
o = 53, but the biggest on is wanted, and it is o+6 = 59.

anonymous · Answer

Ah, yes, that's the correct answer! I thought the difference is not +2 since it's odd numbers and +4 will do too. How about the 2nd question?

larseighner · Answer

No luck so far.  I keep coming up with it is impossible.

anonymous · Answer

The answer in the written sheet is 3. Don't know how to solve it though.

anonymous · Answer

*answer sheet

ikram002p · Answer

ok so u have
$2<log_x 45 <3$
take power x  to all inequalities

$x^2<x^{log_x 45} <x^3$
consider that fact that
$\Huge \color{red }{b^{\log_b x}=x} $
then we would have

$x^2<45  <x^3$

ikram002p · Answer

mmm btw three integer numbers satisfy  4,5,6

ikram002p · Answer

$4^2<45<4^3$
$5^2<45<5^3$
$6^2<45<6^3$

ikram002p · Answer

hope ur getting it

larseighner · Answer

Looks good to me.

anonymous · Answer

Ah, I get it now. Thank you so much everyone!! :D

ikram002p · Answer

np :) your wlc