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find the number that belongs under the radical
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\[\sqrt{\frac{ ? }{ 4}}=3\]
let that o is x...okay..?? then put it in sqrt as under.. \[\sqrt{\frac{ x }{ 4 }}=3\] okay..???
now take square on both sides..to remove sqrt. and then solve it for x. you will get x=9
get it..???or not..?
not really could you explain another to me
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ok..see... taking square on both sides.. \[(\sqrt{\frac{ x }{ 4 }})^2 = 3^2\] now square and sqrt are cncled by each other so the term left is =>\[\frac{ x }{ 4 }=9\] okay..???
now multiply both sides by 4 to make x denominator free...!!then \[\frac{ x }{ 4 }\times4=9\times4\] x=9times4=36 => x=36
ok thank you
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