Question

For the quantum number the = 0, how many possible values are there for the quantum number m subscrip l?

zero
1
2
3

Answer 1

@Somy

Answer 2

oh sorry idk this <.<

Answer 3

It is okay

Answer 4

o.o @superhelp101 and @watermelon14 are same person??

Answer 5

what?? sorry that was suppose to be for someone else, lol!!!

Answer 6

oh lol

Answer 7

n is the principal quantum number and it equals 1, 2, 3... because it denotes the energy level.

l is the angular momentum quantum number and it equals 0, 1, 2, 3... corresponding to the energy sublevels s, p, d, f... respectively. If you know n, the values of l range from 0 to n-1.

m(l) is the magnetic quantum number and it equals ...-2, -1, 0, 1, 2... and it denotes the specific orbital within an sublevel where the electron is located. If you know l, the values of m(l) range from -l to +l

m(s) is the spin quantum number and it equals either +1/2 or -1/2. Each orbital holds 2 electrons, so the spin number is used to identify each of these electrons separately (i.e. one is +1/2 and the other is -1/2).

Now for your question...which quantum number equals 0? Do you mean l = 0? According to what I wrote above, if l = 0, the only possible value for m(l) is 0. This makes B) the right answer! Hope that makes sense!

Answer 8

@matt101 !!! you are here!!!

Answer 9

i mean i rarely see you here <.<

Answer 10

wow thank you very much!

Answer 11

No problem! And @Somy, I do math, biology, chemistry, and physics...so you'll probably see me around more :P

Answer 12

oh i see
i guess im stuck in chemistry and biology more so i don't see u much
lol
ur physics help was amazing! honestly
tho i said bye to physics~ for now <.< @matt101