Question

HELP PLEASE! Find Y if the distance between a and b is 25and b is in the 1st quadrant
A=(3,-18) B=(10,y)

Answer 1

@zaibali.qasmi

Answer 2

use distance formula as written below..

\[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]

here d=25,
x1=3
x2=10
y1=-18
y2=y

put values and solve for y..

Answer 3

What is confusing me is (y-18)^2 would it be y^2+324+49?

Answer 4

@zaibali.qasmi

Answer 5

(y-18)^2=y2-36y+324

Answer 6

actually its (y+18) ^2 = y^2+36y+324

Answer 7

tell us what Y you got when you finished solving the problem.

Answer 8

I got -6 for Y @galacticwavesXX @zaibali.qasmi

Answer 9

since Y is in the first quadrant the answer should be 6. just a sign error

Answer 10

Got it thanks!

Answer 11

no problem.