Solve https://media.glynlyon.com/g_alg01_2012/12/img_test_problem40.gif
Do you want me to take you through, step by step?
suree just show me all your work in i will get it
Sorry, I would rather help you step by step instead of posting a complete solution.
okayy step by step than
\[\frac{b}{6}+\frac{b+2}{8}\ge-\frac{5}{8}\] First lets add the two terms on the left hand side by putting them both over a common denominator, say 48: \[\frac{b}{6}+\frac{b+2}{8}=\frac{?}{48}\ ........(1)\] To find the first term for the numerator on the right hand side of (1), divide 48 by 6 and multiply the result by b. Can you do that?
IM SORRY IDK
The first term for the numerator on the right hand side of (1) is found as follows: \[First\ term=\frac{48}{6} \times b=you\ should\ cope\ with\ this\]
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