Question

0

Answer 1

@Cosmichaotic

Answer 2

Ok so let's first evaluate 7^3.

This is saying [7 x 7 x 7], right?

So what do we get for 7^3?

7^3 = ?

Answer 3

actually it's 7 to the power of 3x

Answer 4

sorry if it's not clear

Answer 5

Ohhhh, very different.

Ok so \[7^{3x}\] correct?

Answer 6

yes

Answer 7

Sorry, I read it wrong before.

Alright, so \[7^{3x} = 9\] is our problem.

First, we must get that 3x out of being in the superscript position.
How we do this is by taking the log of both sides and applying logarithm rules.

\[\ln 7^{3x} = \ln 9 \rightarrow 3x \ln 7 = \ln 9\]

Answer 8

ok

Answer 9

Now let's divide both sides by all the factors besides x.

3xln7 ln9
----- = ---- --> x = ln9/3ln7
3ln7 3ln7

Answer 10

oh ok so i got a after using my calculator