Mathematics
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OpenStudy (anonymous):
cot(x-pi/2) -tanx is undercofunction identities, but it's positive how do i turn it negative
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OpenStudy (anonymous):
@precal
OpenStudy (precal):
no clue, don't know anything about cofunction off the top of my head.....
OpenStudy (precal):
would have to go look it up and I misplaced my precal book, trying to clean my room
OpenStudy (anonymous):
aww okay thanks though
OpenStudy (anonymous):
that is what a cofunction identity is
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OpenStudy (precal):
listen to satellite73
OpenStudy (anonymous):
oh i see the confusion
OpenStudy (anonymous):
but my question is to verify cot(x-pi/2)=-tanx
OpenStudy (anonymous):
\[\cot(\frac{\pi}{2}-x)=\tan(x)\]
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OpenStudy (anonymous):
that is a cofunction identity
OpenStudy (anonymous):
the identity only has cot(pi/2-x)=tanx
OpenStudy (anonymous):
right
OpenStudy (anonymous):
hint: cotangent is odd
OpenStudy (anonymous):
okay ill try it
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OpenStudy (anonymous):
ok but there is nothing much to try
it comes from the fact that cotangent is an odd function and \(x-\frac{\pi}{2}=-(\frac{\pi}{2}-x)\)
OpenStudy (anonymous):
so i just make it negative? @satellite73
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[\cot(-\theta)=-\cot(\theta)\]
OpenStudy (anonymous):
@satellite73 it doesn't make sense to me
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OpenStudy (precal):
those are called even and odd identities