Question

The equation of line AB is (y−3) = 5 (x − 4). What is the slope of a line perpendicular to line AB?

Answer 1

wats sup mathmate

Answer 2

First change the equation to slope-intercept form:
y-3 = 5x-20
y=5x-17
The slope is 5, any line perpendicular to it will have a slope \(-\frac{1}{5}\), i.e. the negative reciprocal of this slope.

Answer 3

okay i see what you did there

Answer 4

hey abmon

Answer 5

Hi @jamestoney
Expand the brackets
Y=mx+c
Y-3=5x-20
Y=5x-17
m represent the gradient(slope )If Two lines with slopes m1 and m2 are perpendicular if and only if m1m2 = -1.
5*m2=-1
m2=-1/5

Answer 6

If two lines are perpendicular, the product of the slopes equals -1.
Or \(a_1*a_2=-1\).
If you know one of the slopes, then the other slope can be found: \(a_2=-\frac{1}{a_1}\)

Answer 7

ok, thanks, just needed it for future refrence

Answer 8

You're welcome! :)