matching points on the graph of g(x) to the value of g'(x)
I know E has the value of g'(x)=0
I do not see 2 negative slopes just one at F
ok C perhaps
c maybe -3 and F maybe -1 not sure
not sure about 1? I felt A and B lined up but it is a sketch
F is much steeper than C right ?
Well if E is zero and C looks like it's not zero, but negative and almost zero.
yes maybe I should have used my ruler, which I just went to go get
so F is -3 and C is -1 in that case, correct?
D is 2
I'm not gonna lie, this graph is fairly ambiguous. However if you can sort of separate them up into which ones are negative and which ones are positive (which you've already kind of done I believe) and then compare them by which ones are steeper, then you can use their relative steepness to sort them out into different points.
using a straight edge to estimate my slopes
maybe this would have been better put on an actual graph where slopes could be determined and then ease into a sketch of points.
ok this is what I think it is, F = -3 C = -1 E=0 A=1/2 B=1 D=2 are there any you disagree with? I took my ruler and made little tangent line and then just pick them to the best of my ability
for 17 do I just write the tangent line y-25=1.5(x-4) and then plug in 3.9, 4, and 4.2 to find the coordinates?
Sorry one moment I've not actually done this so I'm checking 16.
take your time
Ok your points all look correct as far as I can tell, although A and B are really hard to see how they're different, but you made the best choice and I agree with you. So now you're basically just doing number 17 like you describe, so keep up the good work!
Thanks :)
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